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QAIPMT-2008-Ph-2239: NEET 2008 Physics - Class 11 AIPMT-2008-Ph-2239 Solution: A particle of mass m is projected with velocity v making an…
A particle of mass m is projected with velocity v making an angle of with the horizontal. When the particle lands on the level ground the magnitude of the change in its momentum will be:
Multiple Choice Options
- A
- B zero
- C 2mv
- D
Step-by-Step Verified Solution
The magnitude of the resultant velocity at
the point of projection and the landing point is
same.
Clearly, change in momentum along horizontal
(i.e along x-axis)
= mvcos _ � mvcos _ = 0
Change in momentum along vertical (i.e. along
y�axis) = mv sin _ � (�mv sin _ )
= 2 mvsin _ = 2mv _ sin 45�
= 2 m v _ 1 2 = 2 m v
Hence, resultant change in momentum = 2 m v