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QAIPMT-2008-Ch-2231: NEET 2008 Chemistry - Class 11 AIPMT-2008-Ch-2231 Solution: Number of moles of \(MnO_4^-\) required to oxidize one mole of…

Number of moles of MnO4−MnO_4^- required to oxidize one mole of ferrous oxalate completely in acidic medium will be

Multiple Choice Options

  • A 7.5 moles
  • B 0.2 moles
  • C 0.6 moles
  • D 0.4 moles

Step-by-Step Verified Solution

The balanced ionic equation for oxidation of ferrous oxalate by MnO 4 � in acidic medium is as follows : 3MnO 4 - + 5FeC 2 O 4 + 24H + _ 3Mn 2+ + 10CO 2 + 12H 2 O + 5Fe 3+ Thus, 5 moles of FeC 2 O 4 require 3 moles of MnO 4 - . So, 1 mole of FeC 2 O 4 requires = 3 5 = 0.6 moles of MnO 4 -

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