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QAIPMT-2008-Ch-2222: NEET 2008 Chemistry - Class 12 AIPMT-2008-Ch-2222 Solution: Which of the following complexes exhibits the highest…

Which of the following complexes exhibits the highest paramagnetic behaviour? where gly = glycine, en = ethylenediamine and bpy = bipyridyl moieties. (At. nos. Ti = 22, V = 23, Fe = 26, Co = 27)

Multiple Choice Options

  • A [Co(ox)2(OH)2]−[Co(ox)_2(OH)_2]^-
  • B [Ti(NH3)6]3+[Ti(NH_3)_6]^{3+}
  • C [V(gly)2(OH)2(NH3)2]+[V(gly)_2(OH)_2(NH_3)_2]^+
  • D [Fe(en)(bpy)(NH3)2]2+[Fe(en)(bpy)(NH_3)_2]^{2+}

Step-by-Step Verified Solution

In [Co( ox ) 2 (OH) 2 ] _ Co +5 = [Ar] 3d 4 (4 unpaired electrons) OX and OH are weak field ligands. In [Ti(NH 3 ) 6 ] 3+ Ti +3 = [Ar] 3d 1 (one unpaired electron) In [V(gly) 2 (OH) 2 (NH 3 ) 2 ] + V +5 = [Ar] 4r 0 3d 0 (no unpaired electron) In [Fe( en )( bpy )(NH 3 ) 2 ] 2+ Fe +2 = [Ar] 3d 6 (4 unpaired electrons) But due to presence of strong field ligand like NH 3 , bpy and en thus Fe +2 contains no unpaired electron. _ Complex [Co( ox ) 2 (OH) 2 ] _ has maximum number of unpaired electrons, thus show maximum paramagnetism.

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