Verified Solution • 2025–26 Session moderate

QAIPMT-2008-Ch-2208: NEET 2008 Chemistry - Class 12 AIPMT-2008-Ch-2208 Solution: On the basis of the following \(E^ \) values, the strongest…

On the basis of the following E∘E^\circ values, the strongest oxidizing agent is [Fe(CN)6]4−→[Fe(CN)6]3−+e−;E∘=−0.35 V[Fe(CN)_6]^{4-}\rightarrow[Fe(CN)_6]^{3-}+e^-; E^\circ=-0.35\ \text{V}; Fe2+→Fe3++e−;E∘=−0.77 VFe^{2+}\rightarrow Fe^{3+}+e^-; E^\circ=-0.77\ \text{V}

Multiple Choice Options

  • A Fe3+Fe^{3+}
  • B [Fe(CN)6]3−[Fe(CN)_6]^{3-}
  • C [Fe(CN)6]4−[Fe(CN)_6]^{4-}
  • D Fe2+Fe^{2+}

Step-by-Step Verified Solution

Substances which have higher reduction potential are stronger oxidizing agent. [Fe(CN) 6 ] 4 _ _ [Fe(CN) 6 ] 3 _ + e _ ;  E o = _ 0.35 V Fe 2+ _ Fe 3+ + e _ ;  E o = _ 0.77 V Higher the +ve reduction potential, stronger will be the oxidising agent. Oxidising agent oxidises other compounds and gets itself reduced easily.

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