Verified Solution • 2025–26 Session moderate

QAIPMT-2008-Ch-2207: NEET 2008 Chemistry - Class 11 AIPMT-2008-Ch-2207 Solution: Bond dissociation enthalpy of \(H_2\), \(Cl_2\) and HCl are…

Bond dissociation enthalpy of H2H_2, Cl2Cl_2 and HCl are 434, 242 and 431 kJ mol−1431\ \text{kJ mol}^{-1} respectively. Enthalpy of formation of HCl is

Multiple Choice Options

  • A −93 kJ mol−1-93\ \text{kJ mol}^{-1}
  • B 245 kJ mol−1245\ \text{kJ mol}^{-1}
  • C 93 kJ mol−193\ \text{kJ mol}^{-1}
  • D −245 kJ mol−1-245\ \text{kJ mol}^{-1}

Step-by-Step Verified Solution

1 2 H 2 + 1 2 Cl 2 _ HCl, _ H f = ? _ H reaction = [ 1 2 (B.E) H 2 + 1 2 (B.E) Cl 2 ] - (B.E) HCl = [217 + 121] � 431 = 338 � 431 = � 93 kJ mol �1

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