Verified Solution • 2025–26 Session moderate

QAIPMT-2008-Ch-2201: NEET 2008 Chemistry - Class 11 AIPMT-2008-Ch-2201 Solution: If a stands for the edge length of the cubic systems: simple…

If a stands for the edge length of the cubic systems: simple cubic body centred cubic and face centred cubic then the ratio of radii of the spheres in these systems will be respectively 12a:32a:22a\frac{1}{2}a : \frac{\sqrt{3}}{2}a : \frac{\sqrt{2}}{2}a 1a:3a:2a1a : \sqrt{3}a : \sqrt{2}a 12a:34a:122a\frac{1}{2}a : \frac{\sqrt{3}}{4}a : \frac{1}{2\sqrt{2}}a 12a:3a:12a\frac{1}{2}a : \sqrt{3}a : \frac{1}{\sqrt{2}}a

Multiple Choice Options

  • A CHO
  • B CH 4 O
  • C CH 3 O
  • D CH 2 O

Step-by-Step Verified Solution

Element | % | Atomic mass | mole ratio | simple ratio C | 38.71 | 12 | 38.71 12 = 3.22 | 3.22 3.22 = 1 H | 9.67 | 1 | 9.67 1 = 9.67 | 9.67 3.22 = 1 O | 51.62 | 16 | 51.62 16 = 3.22 | 3.22 3.22 = 1 Hence empirical formula of the compound would be CH 3 O

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