Verified Solution • 2025–26 Session moderate

QAIPMT-2007-Ph-2335: NEET 2007 Physics - Class 11 AIPMT-2007-Ph-2335 Solution: A particle of mass m moves in the XY plane with a velocity v…

A particle of mass m moves in the XY plane with a velocity v along the straight line AB. If the angular momentum of the particle with respect to origin O is LAL_A when it is at A and LBL_B when it is at B, then

Multiple Choice Options

  • A LA=LBL_A=L_B
  • B the relationship between LAL_A and LBL_B depends upon the slope of the line AB
  • C LA<LBL_A<L_B
  • D LA>LBL_A>L_B

Step-by-Step Verified Solution

Angular momentum = Linear momentum _ perpendicular distance between line of action of liner momentum from origin Let d be the perpendicular distance. p A and p B be the linear momentum at A and B Angular momentum L A = p A _ d L B = p B _ d So, linear momentum will be equal, i.e., L A = L B .here, p A and p B are equal as have equal velocity. L A = L B

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