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QAIPMT-2006-Ph-2436: NEET 2006 Physics - Class 11 AIPMT-2006-Ph-2436 Solution: 300 J of work is done in sliding a 2 kg block up an inclined…
300 J of work is done in sliding a 2 kg block up an inclined plane of height 10 m. Work done against friction is (Take g = 10 )
Multiple Choice Options
- A 200 J
- B 1000 J
- C 100 J
- D zero
Step-by-Step Verified Solution
Loss in potential energy = mgh
= 2 _ 10 _ 10 = 200 J.
Gain in kinetic energy = work done = 300 J
_ Work done against friction = 300 � 200 = 100 J