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QAIPMT-2006-Ph-2434: NEET 2006 Physics - Class 11 AIPMT-2006-Ph-2434 Solution: A Carnot engine whose sink is at 300 K has an efficiency of…
A Carnot engine whose sink is at 300 K has an efficiency of 40%. By how much should the temperature of source be increased so as to increase its efficiency by 50% of original efficiency?
Multiple Choice Options
- A 380 K
- B 275 K
- C 325 K
- D 250 K
Step-by-Step Verified Solution
We know that efficiency of Carnot Engine
= T 1 _ T 2 T 1
where, T 1 is temp. of source & T 2 is temp. of sink
_ 0.40 = T 1 _ 300 T 1 _ T 1 _ 300 = 0.40 T 1
0.6 T 1 = 300 _ T 1 = 300 0.6 = 3000 6 = 500 K
Now efficiency to be increased by 50%
_ 0.60 = T 1 _ 300 T 1 _ T 1 _ 300 = 0.6 T 1
0.4 T 1 = 300 _ T 1 = 300 0.4 = 300 _ 10 4 = 750
Increase in temp = 750 � 500 = 250 K