Verified Solution • 2025–26 Session moderate

QAIPMT-2006-Ch-2380: NEET 2006 Chemistry - Class 11 AIPMT-2006-Ch-2380 Solution: Consider the reaction: $N_2(g) + 3H_2(g) 2NH_3(g)$ The…

Consider the reaction:

N_2(g) + 3H_2(g) \rightleftharpoons 2NH_3(g)

The equality relationship between

\frac{d[NH_3]}{dt}

and

-\frac{d[H_2]}{dt}

\frac{d[NH_3]}{dt} = -\frac{d[H_2]}{dt}

\frac{d[NH_3]}{dt} = -\frac{1}{3}\frac{d[H_2]}{dt}

+\frac{d[NH_3]}{dt} = -\frac{2}{3}\frac{d[H_2]}{dt}

+\frac{d[NH_3]}{dt} = -\frac{3}{2}\frac{d[H_2]}{dt}

A The reaction is exothermic.
B At equilibrium, the concentrations of CO 2(g) and H 2 O (l) are not equal.
C The equilibrium constant for the reaction is given by K p = ${{\left[ {C{O_2}} \right]} \over {\left[ {C{H_4}} \right]\left[ {{O_2}} \right]}}$ [ C H 4 _ ] [ O 2 _ ] [ C O 2 _ ] _
D Addition of CH 4(g) or O 2(g) at equilibrium will cause a shift to the right.

Step-by-Step Verified Solution

Option C is incorrect as the value of K P given is wrong. It should have been K P = P C O 2 P C H 4 _ [ P O 2 ] 2