Verified Solution • 2025–26 Session moderate

QAIPMT-2005-Ph-2570: NEET 2005 Physics - Class 12 AIPMT-2005-Ph-2570 Solution: In the reaction \(_1^2H+_1^3H _2^4He+_0^1n\), if the binding…

In the reaction 12H+13H→24He+01n_1^2H+_1^3H\rightarrow_2^4He+_0^1n, if the binding energies of 12H_1^2H, 13H_1^3H and 24He_2^4He are respectively a, b and c (in MeV), then the energy (in MeV) released in this reaction is

Multiple Choice Options

  • A a+b+ca+b+c
  • B a+b−ca+b-c
  • C c−a−bc-a-b
  • D c+a−bc+a-b

Step-by-Step Verified Solution

Energy released in given reaction = BE of products � BE of reactants = c � (a+ b) = c � a � b

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