Verified Solution • 2025–26 Session moderate

QAIPMT-2005-Ph-2549: NEET 2005 Physics - Class 11 AIPMT-2005-Ph-2549 Solution: Two boys are standing at the ends A and B of a ground where AB…

Two boys are standing at the ends A and B of a ground where AB = a. The boy at B starts running in a direction perpendicular to AB with velocity v1v_1. The boy at A starts running simultaneously with velocity v and catches the other in a time t, where t is

Multiple Choice Options

  • A av2+v12\frac{a}{\sqrt{v^2+v_1^2}}
  • B av+v1\frac{a}{v+v_1}
  • C av−v1\frac{a}{v-v_1}
  • D av2−v12\sqrt{\frac{a}{v^2-v_1^2}}

Step-by-Step Verified Solution

Velocity of A relative to B is given by v A / B _ = v A _ _ v B _ = v _ _ v 1 _     ...(i) By taking x-components of equation (i), we get 0 = v sin _ _ _ v 1 _ sin _ _ = v 1 v     ...(ii) By taking Y-components of equation (i), we get v y = v cos _ _     ...(iii) Time taken by boy at A to catch the boy at B is given by t = Relative d i s p l a c e m e n t a l o n g Y _ a x i s Relative v e l o c i t y a l o n g Y _ a x i s = a v cos _ _ = a v . 1 _ sin 2 _ = a v . 1 _ ( v 1 v ) 2 [From equation (i)] = a v . v 2 _ v 1 2 v 2 = a v 2 _ v 1 2 = a 2 v 2 _ v 1 2

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