Verified Solution • 2025–26 Session moderate

QAIPMT-2005-Ch-2503: NEET 2005 Chemistry - Class 11 AIPMT-2005-Ch-2503 Solution: The energy of second Bohr orbit of the hydrogen atom is \(-328\ …

The energy of second Bohr orbit of the hydrogen atom is −328 kJ mol−1-328\ \text{kJ mol}^{-1}; hence the energy of fourth Bohr orbit would be

Multiple Choice Options

  • A −41 kJ mol−1-41\ \text{kJ mol}^{-1}
  • B −82 kJ mol−1-82\ \text{kJ mol}^{-1}
  • C −164 kJ mol−1-164\ \text{kJ mol}^{-1}
  • D −1312 kJ mol−1-1312\ \text{kJ mol}^{-1}

Step-by-Step Verified Solution

E n = -K ( Z n ) 2 Z = 1; n = 2 E 2 = _ K _ 1 4 _ E 2 = -328 kJ mol -1 ; K = 4 _ 328 E 4 = _ K _ 1 16 _ E 4 = -4 _ 328 1 16 = -82 kJ mol -1

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