Verified Solution • 2025–26 Session moderate

QAIPMT-2005-Ch-2498: NEET 2005 Chemistry - Class 11 AIPMT-2005-Ch-2498 Solution: At \(25^ C\), the dissociation constant of a base, BOH, is…

At 25∘C25^\circ C, the dissociation constant of a base, BOH, is 1.0×10−121.0\times10^{-12}. The concentration of hydroxyl ions in 0.01 M aqueous solution of the base would be

Multiple Choice Options

  • A 1.0×10−5 mol L−11.0\times10^{-5}\ \text{mol L}^{-1}
  • B 1.0×10−6 mol L−11.0\times10^{-6}\ \text{mol L}^{-1}
  • C 2.0×10−6 mol L−12.0\times10^{-6}\ \text{mol L}^{-1}
  • D 1.0×10−7 mol L−11.0\times10^{-7}\ \text{mol L}^{-1}

Step-by-Step Verified Solution

BOH | _ | B + | + | OH - Initially | C | 0 | 0 At equilibbrium | C - C _ | C _ | C _ [OH - ] = C _ _ [OH - ] = K b C _ [OH - ] = 1 _ 10 _ 12 _ 10 _ 2 = 1.0 _ 10 _ 7 mol L _ 1

Related Learning Resources & Exam Preparation

NEET PYQ Question Bank
Browse year-wise authentic previous years' questions with solutions
Authentic CBT Mock Tests
Simulate official exam environment with live timer and percentile scoring