Verified Solution • 2025–26 Session moderate

QAIPMT-2004-Ph-2655: NEET 2004 Physics - Class 11 AIPMT-2004-Ph-2655 Solution: If \(

If ∣A⃗×B⃗∣=3A⃗⋅B⃗|\vec{A}\times\vec{B}|=\sqrt{3}\vec{A}\cdot\vec{B} then the value of ∣A⃗+B⃗∣|\vec{A}+\vec{B}| is

Multiple Choice Options

  • A (A2+B2+AB)1/2(A^2+B^2+AB)^{1/2}
  • B (A2+B2+AB3)1/2\left(A^2+B^2+\frac{AB}{\sqrt{3}}\right)^{1/2}
  • C A+BA+B
  • D (A2+B2+3AB)1/2(A^2+B^2+\sqrt{3}AB)^{1/2}

Step-by-Step Verified Solution

| A _ _ B _ | = A B sin _ _ A _ B _ = A B cos _ _ | A _ _ B _ | = 3 A _ B _ _ A B sin _ _ = 3 A B cos _ _ _ tan _ _ = 3     _ _ = 60 o _ | A _ _ B _ | = A 2 + B 2 + 2 A B cos _ 60 _ = A 2 + B 2 + A B = (A 2 + b 2 + AB) 1/2

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