Verified Solution • 2025–26 Session moderate

QAIPMT-2004-Ph-2628: NEET 2004 Physics - Class 11 AIPMT-2004-Ph-2628 Solution: A round disc of moment of inertia \(I_2\) about its axis…

A round disc of moment of inertia I2I_2 about its axis perpendicular to its plane and passing through its centre is placed over another disc of moment of inertia I1I_1 rotating with an angular velocity ω\omega about the same axis. The final angular velocity of the combination of discs is

Multiple Choice Options

  • A I2ωI1+I2\frac{I_2\omega}{I_1+I_2}
  • B ω\omega
  • C I1ωI1+I2\frac{I_1\omega}{I_1+I_2}
  • D (I1+I2)ωI1\frac{(I_1+I_2)\omega}{I_1}

Step-by-Step Verified Solution

The initial angular momentum of the system is I 1 _ and final angular momentum is ( I 1 + I 2 ) _ _ where _ _ = final angular velocity of combination of discs On equating the initial and final angular momentum, we get _ _ = I 1 _ ( I 1 + I 2 )

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