Verified Solution • 2025–26 Session moderate

QAIPMT-2004-Ph-2619: NEET 2004 Physics - Class 11 AIPMT-2004-Ph-2619 Solution: A particle of mass \(m_1\) is moving with a velocity \(v_1\)…

A particle of mass m1m_1 is moving with a velocity v1v_1 and another particle of mass m2m_2 is moving with a velocity v2v_2. Both of them have the same momentum but their different kinetic energies are E1E_1 and E2E_2 respectively. If m1>m2m_1>m_2 then:

Multiple Choice Options

  • A E1<E2E_1<E_2
  • B E1E2=m1m2\frac{E_1}{E_2}=\frac{m_1}{m_2}
  • C E1>E2E_1>E_2
  • D E1=E2E_1=E_2

Step-by-Step Verified Solution

Kinetic energy = p 2 2 m E 1 E 2 = p 1 2 / 2 m 1 p 2 2 / 2 m 2 _ E 1 E 2 = m 2 m 1 as m 1 > m 2 _ E 1 < E 2

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