Verified Solution • 2025–26 Session moderate

QAIPMT-2004-Ph-2617: NEET 2004 Physics - Class 12 AIPMT-2004-Ph-2617 Solution: A galvanometer of 50 ohm resistance has 25 divisions. A current …

A galvanometer of 50 ohm resistance has 25 divisions. A current of

4\times10^{-4}

ampere gives a deflection of one division. To convert this galvanometer into a voltmeter having a range of 25 volts, it should be connected with a resistance of

Multiple Choice Options

A $2500\Omega$ as a shunt
B $2450\Omega$ as a shunt
C $2550\Omega$ in series
D $2450\Omega$ in series

Step-by-Step Verified Solution

The total current shown by the galvanometer, I g = 25 _ 4 _ 10 -4 A = 10 -2 A The value of resistance connected in series to convert galvanometer into voltmeter of 25 V is V = I g (R e + R g ) _ R e = V I g _ R g = 2450 �

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