Verified Solution • 2025–26 Session moderate

QAIPMT-2004-Ch-2594: NEET 2004 Chemistry - Class 11 AIPMT-2004-Ch-2594 Solution: If the bond energies of H-H, Br-Br, and H-Br are 433, 192 and…

If the bond energies of H-H, Br-Br, and H-Br are 433, 192 and

364\ \text{kJ mol}^{-1}

respectively, the

\Delta H^\circ

for the reaction

H_2(g)+Br_2(g)\rightarrow 2HBr(g)

Multiple Choice Options

A $-261$ kJ
B +103 kJ
C +261 kJ
D $-103$ kJ

Step-by-Step Verified Solution

H 2 (g) + Br 2(g) _ 2HBr (g) , _ H o f = ? _ H o f = _ (B.E.) reactants � _ (B.E.) products = (B.E.) H�H + (B.E.) Br�Br �2(B.E) H-Br = [433 + 192] � 2(364) kJ mol �1 = (625 � 728) kJ mol �1 = �103 kJ mol �1

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