Verified Solution • 2025–26 Session moderate

QAIPMT-2004-Ch-2590: NEET 2004 Chemistry - Class 11 AIPMT-2004-Ch-2590 Solution: The frequency of radiation emitted when the electron falls from …

The frequency of radiation emitted when the electron falls from n = 4 to n = 1 in hydrogen atom will be (Given ionization energy of H = 2.18×10−18 J atom−12.18\times10^{-18}\ \text{J atom}^{-1} and h = 6.625×10−346.625\times10^{-34} J s)

Multiple Choice Options

  • A 1.54×1015 s−11.54\times10^{15}\ \text{s}^{-1}
  • B 1.03×1015 s−11.03\times10^{15}\ \text{s}^{-1}
  • C 3.08×1015 s−13.08\times10^{15}\ \text{s}^{-1}
  • D 2.00×1015 s−12.00\times10^{15}\ \text{s}^{-1}

Step-by-Step Verified Solution

E = h v or v = E/h For H atom, E = _ 21.76 _ 10 _ 19 n 2 J a t m _ 1 _ E = _ 21.76 _ 10 _ 19 ( 1 4 2 _ 1 1 2 ) = 20.40 _ 10 -19 J atm -1 v = 20.40 _ 10 _ 19 6.626 _ 10 _ 34 = 3.079 _ 10 15 s -1

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