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QAIPMT-2003-Ph-2713: NEET 2003 Physics - Class 12 AIPMT-2003-Ph-2713 Solution: Three capacitors each of capacity \(4\ F\) are to be connected…

Three capacitors each of capacity 4 μF4\ \mu F are to be connected in such a way that the effective capacitance is 6 μF6\ \mu F. This can be done by

Multiple Choice Options

  • A connecting all of them in series
  • B connecting them in parallel
  • C connecting two in series and one in parallel
  • D connecting two in parallel and one in series

Step-by-Step Verified Solution

For series, C _ = C 1 _ C 2 C 1 + C 2 = 4 _ 4 4 + 4 = 2 _ F For parallel C e q = C _ + C 3 = 2 + 4 = 6 _ F

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