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QAIPMT-2003-Ch-2697: NEET 2003 Chemistry - Class 12 AIPMT-2003-Ch-2697 Solution: The reaction \(A B\) follows first order kinetics. The time…
The reaction follows first order kinetics. The time taken for 0.8 mole of A to produce 0.6 mole of B is 1 hour. What is the time taken for conversion of 0.9 mole of A to produce 0.675 mole of B?
Multiple Choice Options
- A 1 hour
- B 0.5 hour
- C 0.25 hour
- D 2 hours
Step-by-Step Verified Solution
For first order reaction
k = 2.303 t log _ [ A ] 0 [ A ] t
_ k = 2.303 1 log _ 0.8 0.2 = 2.303 log 4 ....(1)
Let t 1 hour is required for changing the concentration
of A from 0.9 mole to 0.675 mole of B.
Remaining mole of A = 0.9 � 0.675 = 0.225
_ k = 2.303 t 1 log _ 0.9 0.225 .....(2)
From equation (1) and (2)
2.303 t 1 log _ 0.9 0.225 = 2.303 log 4
_ t 1 = 1 hr