Verified Solution • 2025–26 Session moderate

QAIPMT-2003-Ch-2693: NEET 2003 Chemistry - Class 11 AIPMT-2003-Ch-2693 Solution: The oxidation states of sulphur in the anions \(SO_3^{2-}\),…

The oxidation states of sulphur in the anions SO32−SO_3^{2-}, S2O42−S_2O_4^{2-} and S2O62−S_2O_6^{2-} follow the order

Multiple Choice Options

  • A S2O42−<SO32−<S2O62−S_2O_4^{2-}<SO_3^{2-}<S_2O_6^{2-}
  • B SO32−<S2O42−<S2O62−SO_3^{2-}<S_2O_4^{2-}<S_2O_6^{2-}
  • C S2O42−<S2O62−<SO32−S_2O_4^{2-}<S_2O_6^{2-}<SO_3^{2-}
  • D S2O62−<S2O42−<SO32−S_2O_6^{2-}<S_2O_4^{2-}<SO_3^{2-}

Step-by-Step Verified Solution

SO 3 2� : oxidation state of �S� is +4 S 2 O 4 2� : oxidation state of �S� is +3. S 2 O 6 2� : oxidation state of �S� is +5. So, the order is S 2 O 4 2 _ < SO 3 2 _ < S 2 O 6 2 _ .

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