Verified Solution • 2025–26 Session moderate

QAIPMT-2003-Ch-2684: NEET 2003 Chemistry - Class 11 AIPMT-2003-Ch-2684 Solution: The densities of graphite and diamond at 298 K are 2.25 and…

The densities of graphite and diamond at 298 K are 2.25 and

3.31\ \text{g cm}^{-3}

, respectively. If the standard free energy difference (

\Delta G^\circ

) is equal to

1895\ \text{J mol}^{-1}

, the pressure at which graphite will be transformed into diamond at 298 K is

Multiple Choice Options

A $11.14\times10^8$ Pa
B $11.14\times10^7$ Pa
C $11.14\times10^6$ Pa
D $11.14\times10^5$ Pa

Step-by-Step Verified Solution

C (graphite) _ C (diamond) Volume of graphite = 12 2.25 = 5.33 cm 3 mol �1 Volume of diamond = 12 3.31 = 3.63 cm 3 mol �1 _ V = V graphite � V diamond = 1.70 cm 3 mol �1 = 1.70 _ 10 �3 L mol �1 So, _ G o = P _ V _ 1895 J mol �1 = P(1.70 _ 10 �3 L mol �1 ) _ 1114.70 _ 10 3 J/L = P _ 1114.7 _ 10 3 101.33 = P _ P = 11000.69 atm _ 1.013 _ 10 5 Pa = 11143.69 _ 10 5 Pa = 11.14 _ 10 8 Pa

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