Verified Solution • 2025–26 Session moderate

QAIPMT-2003-Ch-2675: NEET 2003 Chemistry - Class 12 AIPMT-2003-Ch-2675 Solution: On the basis of the information available from the reaction, \( …

On the basis of the information available from the reaction, 43Al+O2→23Al2O3\frac{4}{3}Al+O_2\rightarrow\frac{2}{3}Al_2O_3, ΔG=−827 kJ mol−1\Delta G=-827\ \text{kJ mol}^{-1} of O2O_2, the minimum e.m.f. required to carry out an electrolysis of Al2O3Al_2O_3 is (F = 96500 C mol−1^{-1})

Multiple Choice Options

  • A 2.14 V
  • B 4.28 V
  • C 6.42 V
  • D 8.56 V

Step-by-Step Verified Solution

4/3Al + O 2 _ 2/3Al 2 O 3 ,    _ G = _ 827 kJ mol _ 1 For 1 mol of Al, n = 3 _ For 4 3 mol of Al, n = 3 _ 4 3 = 4 As _ G = - nFE o _ � 827 _ 10 3 J = � 4 _ E� _ 96500 _ E o = 827 _ 10 3 4 _ 96500 = 2.14 V

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