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QAIPMT-2003-Ch-2669: NEET 2003 Chemistry - Class 12 AIPMT-2003-Ch-2669 Solution: The e.m.f. of a Daniell cell at 298 K is $E_1$. When the…

The e.m.f. of a Daniell cell at 298 K is

E_1

. When the concentration of

ZnSO_4

is 1.0 M and that of

CuSO_4

is 0.01 M, the e.m.f. changed to

E_2

. What is the relationship between

E_1

and

E_2

Multiple Choice Options

A $E_1>E_2$
B $E_1<E_2$
C $E_1=E_2$
D $E_2=0\neq E_1$

Step-by-Step Verified Solution

Cell reaction is, Zn + Cu 2+ _ Zn 2+ + Cu E cell = E o cell - R T n F ln _ [ Z n 2 + ] [ C u 2 + ] Greater the factor [ Z n 2 + ] [ C u 2 + ] , less is the EMF. Hence E 1 > E 2

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QAIPMT-2003-Ch-2669: NEET 2003 Chemistry - Class 12 AIPMT-2003-Ch-2669 Solution: The e.m.f. of a Daniell cell at 298 K is \(E_1\). When the…

Multiple Choice Options

Step-by-Step Verified Solution

Related Learning Resources & Exam Preparation