Verified Solution • 2025–26 Session moderate

QAIPM-2002-Ph-2850: NEET 2002 Physics - Class 11 AIPM-2002-Ph-2850 Solution: An object of mass 3 kg is at rest. Now a force of \( {F}=6t^2…

An object of mass 3 kg is at rest. Now a force of

\vec{F}=6t^2\hat{i}+4t\hat{j}

is applied on the object then velocity of object at t = 3 sec. is

Multiple Choice Options

A $18\hat{i}+3\hat{j}$
B $18\hat{i}+6\hat{j}$
C $3\hat{i}+18\hat{j}$
D $18\hat{i}+4\hat{j}$

Step-by-Step Verified Solution

Mass (m) = 3 kg, force (F) = 6 t 2 i ^ + 4 t j ^ _ acceleration a = F / m = 6 t 2 i ^ + 4 t j ^ 3 = 2 t 2 i ^ + 4 3 t j ^ Now, a = d v d t = 2 t 2 i ^ + 4 3 t j ^ d v = ( 2 t 2 i ^ + 4 3 t j ^ ) d t _ v = � 0 3 ( 2 t 2 i ^ + 4 3 t j ^ ) d t = 2 3 t 3 i ^ + 4 6 t 2 j ^ | 0 3 = 18 i ^ + 6 j ^

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