Verified Solution • 2025–26 Session moderate

QAIPM-2002-Ph-2836: NEET 2002 Physics - Class 12 AIPM-2002-Ph-2836 Solution: For a cell terminal potential difference is 2.2 V when circuit…

For a cell terminal potential difference is 2.2 V when circuit is open and reduces to 1.8 V when cell is connected to a resistance of R = 5Ω5\Omega. Determine internal resistance of cell (r)

Multiple Choice Options

  • A 109Ω\frac{10}{9}\Omega
  • B 910Ω\frac{9}{10}\Omega
  • C 119Ω\frac{11}{9}\Omega
  • D 59Ω\frac{5}{9}\Omega

Step-by-Step Verified Solution

Terminal potential difference is 2.2 V when circuit is open. _ e.m.f. of the cell = E = 2.2 volt Now, when the cell is connected to the external resistance, circuit current I is given by I = E R + r = 2.2 5 + r ampere, where r is the internal resistance of the cell. Potential difference across the cell = IR = 2.2 5 + r _ 5 = 1.8 _ 5 + r = 11/1.8. _ r = 11 1.8 _ 5 = 110 _ 90 18 = 10 9 �

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