Verified Solution • 2025–26 Session moderate

QAIPM-2002-Ph-2832: NEET 2002 Physics - Class 12 AIPM-2002-Ph-2832 Solution: For a series LCR circuit the power loss at resonance is

For a series LCR circuit the power loss at resonance is

Multiple Choice Options

A $\frac{V^2}{[\omega L-\frac{1}{\omega C}]}$
B $I^2L\omega$
C $I^2R$
D $\frac{V^2}{C\omega}$

Step-by-Step Verified Solution

The impedance Z of a series LCR circuit is given by, Z = R 2 + ( X L _ X C ) 2 At resonance, X L = X C , hence Z = R. Let, supply voltage = V R = V _ R.M.S. current, I = V R _ Power loss = VI = I 2 R

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