Verified Solution • 2025–26 Session moderate

QAIPM-2002-Ph-2830: NEET 2002 Physics - Class 11 AIPM-2002-Ph-2830 Solution: A wave travelling in positive X-direction with a = 0.2 \(…

A wave travelling in positive X-direction with a = 0.2 ms−2\text{ms}^{-2}, velocity = 360 ms−1\text{ms}^{-1} and λ\lambda = 60 m, then correct expression for the wave is

Multiple Choice Options

  • A y=0.2sin⁡[2π(6t+x60)]y=0.2\sin[2\pi(6t+\frac{x}{60})]
  • B y=0.2sin⁡[π(6t+x60)]y=0.2\sin[\pi(6t+\frac{x}{60})]
  • C y=0.2sin⁡[2π(6t−x60)]y=0.2\sin[2\pi(6t-\frac{x}{60})]
  • D y=0.2sin⁡[π(6t−x60)]y=0.2\sin[\pi(6t-\frac{x}{60})]

Step-by-Step Verified Solution

The equation of progressive wave travelling in positive x-direction is given by y = a sin _ 2 � _ ( v t _ x ) Here a = 0.2 m, v = 360 m/sec, _ = 60 m _ y = 0.2 sin _ 2 � 60 ( 360 t _ x ) = 0.2 s i n [ 2 � ( 6 t _ x 60 ) ]

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