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QAIPM-2002-Ph-2818: NEET 2002 Physics - Class 11 AIPM-2002-Ph-2818 Solution: The efficiency of Carnot engine is 50% and temperature of sink…
The efficiency of Carnot engine is 50% and temperature of sink is 500 K. If temperature of source is kept constant and its efficiency raised to 60%, then the required temperature of sink will be
Multiple Choice Options
- A 100 K
- B 600 K
- C 400 K
- D 500 K
Step-by-Step Verified Solution
Efficiency ( _ ) of a carnot engine is given by
_ = 1 _ T 2 T 1 , where T 1 is the temperature of the source and T 2 is the temperature of the sink.
Here, T 2 = 500 K
_ 0.5 = 1 _ 500 T 1 _ T 1 = 1000 K
Now, _ = 0.6 = 1 _ T 2 _ 1000 (T 2 ' is the new sink
temperature)
_ T 2 _ = 400 K