Verified Solution • 2025–26 Session moderate

QAIPM-2002-Ch-2802: NEET 2002 Chemistry - Class 11 AIPM-2002-Ch-2802 Solution: Solution of 0.1 N \(NH_4OH\) and 0.1 N \(NH_4Cl\) has pH 9.25.…

Solution of 0.1 N NH4OHNH_4OH and 0.1 N NH4ClNH_4Cl has pH 9.25. Then find out pKbpK_b of NH4OHNH_4OH

Multiple Choice Options

  • A 9.25
  • B 4.75
  • C 3.75
  • D 8.25

Step-by-Step Verified Solution

NH 4 OH and NH 4 Cl constitute to form a basic buffer. pOH = pK b + log [ S a l t ] [ B a s e ] We know, pOH+ pH = 14 or pOH = 14 � pH _ 14 - pH - log _ [ S a l t ] [ B a s e ] = pK b _ 14 - 9.25 - log _ 0.1 0.1 = pK b _ 14 � 9.25 � 0 = pK b _ pK b = 4.75

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