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QAIPM-2001-Ch-2853: NEET 2002 Physics - Class 12 AIPM-2001-Ch-2853 Solution: Identical charges (-q) are placed at each corner of cube of…

Identical charges (-q) are placed at each corner of cube of side b then electrostatic potential energy of charge (+q) which is placed at centre of cube will be

Multiple Choice Options

  • A −42q2πϵ0b-\frac{4\sqrt{2}q^2}{\pi\epsilon_0 b}
  • B −82q2πϵ0b-\frac{8\sqrt{2}q^2}{\pi\epsilon_0 b}
  • C −4q23πϵ0b-\frac{4q^2}{\sqrt{3}\pi\epsilon_0 b}
  • D 82q24πϵ0b\frac{8\sqrt{2}q^2}{4\pi\epsilon_0 b}

Step-by-Step Verified Solution

There are eight corners of a cube and in each corner there is a charge of (�q). At the centre of the corner there is a charge of (+q). Each corner is equidistant from the centres of the cube and the distance (d) is half of the diagonals of the cube. Diagonal of the cube = b 2 + b 2 + b 2 = 3 b _ d = 3 b / 2 Now, electric potential energy of the charge (+q) due to a charge (�q) at one corner U = q 1 q 2 4 � _ 0 r = ( + q ) _ ( _ q ) 4 � _ 0 ( 3 b / 2 ) = _ q 2 2 � _ 0 ( 3 b ) _ Total electric potential energy due to all the eight identical charges = 8 U = _ 8 q 2 2 � _ 0 3 b = _ 4 q 2 3 � _ 0 b

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