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QAIPM-2001-Ch-2852: NEET 2002 Physics - Class 11 AIPM-2001-Ch-2852 Solution: For a black body at temperature \(727^ C\), its radiating power …
For a black body at temperature , its radiating power is 60 watt and temperature of surrounding is . If temperature of black body is changed to then its radiating power will be
Multiple Choice Options
- A 304 W
- B 320 W
- C 240 W
- D 120 W
Step-by-Step Verified Solution
Radiating power of a black body
= E 0 = _ ( T 4 _ T 0 4 ) A
where _ is known as the Stefan-Boltzmann constant, A is the surface area of a black body, T is the temperature of the black body and T 0 is the temperature of the surrounding.
_ 60 = _ (1000 4 � 500 4 ) ...(i)
[T = 727 o C = 727 + 273 = 1000 K, T0 = 227 o C = 500 K].
In the second case, T = 1227 o C = 1500 K and let E' be the radiating power.
_ E' = _ (1500 4 � 500 4 ) ...(ii)
From (i) and (ii) we have
E _ 60 = 1500 4 _ 500 4 1000 4 _ 500 4 = 15 4 _ 5 4 10 4 _ 5 4 = 50000 9375
_ E _ = 50000 9375 _ 60 = 320 W