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QAIPM-2001-Ph-2930: NEET 2001 Physics - Class 12 AIPM-2001-Ph-2930 Solution: In Thomson mass spectrograph \( {E}{B}=v\) then the velocity of …

In Thomson mass spectrograph EB=v\frac{E}{B}=v then the velocity of electron beam will be

Multiple Choice Options

  • A ∣E∣∣B∣\frac{|E|}{|B|}
  • B E×BE\times B
  • C ∣B∣∣E∣\frac{|B|}{|E|}
  • D E2B2\frac{E^2}{B^2}

Step-by-Step Verified Solution

As eE = evB _ v = | E _ | | B _ |

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