Verified Solution • 2025–26 Session moderate

QAIPM-2001-Ch-2889: NEET 2001 Chemistry - Class 11 AIPM-2001-Ch-2889 Solution: \(PbO_2 PbO; G_{298} 0\). Most probable oxidation state of Pb…

PbO2→PbO;ΔG298<0PbO_2\rightarrow PbO; \Delta G_{298}<0 and SnO2→SnO;ΔG298>0SnO_2\rightarrow SnO; \Delta G_{298}>0. Most probable oxidation state of Pb and Sn will be

Multiple Choice Options

  • A Pb4+,Sn4+Pb^{4+}, Sn^{4+}
  • B Pb4+,Sn2+Pb^{4+}, Sn^{2+}
  • C Pb2+,Sn2+Pb^{2+}, Sn^{2+}
  • D Pb2+,Sn4+Pb^{2+}, Sn^{4+}

Step-by-Step Verified Solution

PbO 2 _ PbO Pb has +4 oxidation state In PbO 2 . Pb has +2 oxidation state In PbO. Here _ G is negative that is why reaction is spontaneous and Pb 4+ reduces Pb 2+ thus, Pb 2+ is most probable oxidation state of Pb. SnO 2 _ SnO; Sn has +4 oxidation state In SnO 2 . Sn has +2 oxidation state In SnO. _ G is positive that is why reaction is not spontaneous thus, +4 oxidation state of Sn is more stable as it does not change to +2 oxidation state spontaneously.

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