Verified Solution • 2025–26 Session moderate

QAIPM-2001-Ch-2868: NEET 2001 Chemistry - Class 11 AIPM-2001-Ch-2868 Solution: Change in enthalpy for reaction, \(2H_2O_2(l) 2H_2O(l)+O_2(g)\) …

Change in enthalpy for reaction, 2H2O2(l)→2H2O(l)+O2(g)2H_2O_2(l)\rightarrow 2H_2O(l)+O_2(g) if heat of formation of H2O2(l)H_2O_2(l) and H2O(l)H_2O(l) are -188 and -286 kJ/mol respectively, is

Multiple Choice Options

  • A −196-196 kJ/mol
  • B +196 kJ/mol
  • C +948 kJ/mol
  • D −948-948 kJ/mol

Step-by-Step Verified Solution

2H 2 O 2(l) _ 2H 2 O (l) + O 2(g) , _ H r = ? H 2(g) + O 2(g) _ H 2 O 2(l) , _ H = � 188 kJ mol ...(1) H 2(g) + O 2(g) _ H 2 O (l) , _ H = �286 kJ/mol ....(2) (1) - (2) H 2 O 2(l) _ H 2 O (l) + 1 2 O 2(g) _ H = �286 � (� 188) = �98 kJ mol �1 Multiplying this equation by 2 we get the required equation 2H 2 O 2(l) _ 2H 2 O (l) + O 2(g) _ H = 2 (� 98) kJ/mol = � 196 kJ/mol

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