QAIPM-2000-Ch-2964: NEET 2000 Chemistry - Class 11 AIPM-2000-Ch-2964 Solution: Right order of dissociation energy \(N_2\) and \(N_2^+\) is

N 2 has 14 electrons. Moleculer orbital configuration of N 2 = _ 1 s 2 _ 1 s 2 _ _ 2 s 2 _ 2 s 2 _ � 2 p x 2 = � 2 p y 2 _ 2 p z 2 _ N b = 10 N a = 4 _ BO = 1 2 [ 10 _ 4 ] = 3 N 2 + has 13 electrons. Moleculer orbital configuration of N 2 + = _ 1 s 2 _ 1 s 2 _ _ 2 s 2 _ 2 s 2 _ � 2 p x 2 = � 2 p y 2 _ 2 p z 1 _ N b = 9 N a = 4 _ BO = 1 2 [ 9 _ 4 ] = 2.5 As the bond order in N 2 is more than N 2 + so the dissociation energy of N 2 is higher than N 2 + .