Verified Solution • 2025–26 Session moderate

QJEEM25Phd818: JEE Main 2025 Physics - Class 12 JEEM25Phd818 Solution: An electron is made to enter symmetrically between two parallel …

An electron is made to enter symmetrically between two parallel and equally but oppositely charged metal plates, each of 10 cm length. The electron emerges out of the electric field region with a horizontal component of velocity 106 m/s10^6 \mathrm{~m} / \mathrm{s} . If the magnitude of the electric field between the plates is 9.1 V/cm9.1 \mathrm{~V} / \mathrm{cm} , then the vertical component of velocity of electron is (mass of electron =9.1×10−31 kg=9.1 \times 10^{-31} \mathrm{~kg} and charge of electron =1.6×10−19C=1.6 \times 10^{-19} \mathrm{C} )

Multiple Choice Options

  • A 1×106 m/s1 \times 10^6 \mathrm{~m} / \mathrm{s}
  • B 16×106 m/s16 \times 10^6 \mathrm{~m} / \mathrm{s}
  • C 16×104 m/s16 \times 10^4 \mathrm{~m} / \mathrm{s}
  • D 0

Step-by-Step Verified Solution

JEE Main 2025 (Online) 22nd January Morning Shift Physics - Capacitor Question 7 English Explanation

⇒t=ℓVx=10×10−2106=10−7⇒ Vy=uy+ayt⇒ Vy=0+eE m×10−7⇒ Vy=1.6×10−199.1×10−31×9.1×10−2×10−7⇒ Vy=16×106

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