Verified Solution • 2025–26 Session moderate

QJEEM25Phd2f6: JEE Main 2025 Physics - Class 12 JEEM25Phd2f6 Solution: In the first configuration (1) as shown in the figure, four…

JEE Main 2025 (Online) 24th January Evening Shift Physics - Electrostatics Question 3 English

In the first configuration (1) as shown in the figure, four identical charges (q0)\left(q_0\right) are kept at the corners A, B, C and D of square of side length ' aa '. In the second configuration (2), the same charges are shifted to mid points G,E,HG, E, H and FF , of the square. If K=14πϵ0K=\frac{1}{4 \pi \epsilon_0} , the difference between the potential energies of configuration (2) and (1) is given by :

Multiple Choice Options

  • A Kq02a(4−22)\frac{K q_0^2}{a}(4-2 \sqrt{2})
  • B Kq02a(42−2)\frac{K q_0^2}{a}(4 \sqrt{2}-2)
  • C Kq02a(3−2)\frac{\mathrm{Kq}_0^2}{\mathrm{a}}(3-\sqrt{2})
  • D Kq02a(32−2)\frac{\mathrm{Kq}_0^2}{\mathrm{a}}(3 \sqrt{2}-2)

Step-by-Step Verified Solution

U1=4Kq02a+2Kq022a=Kq02a(4+2)U2=Kq02(a2)(4+2)=Kq02a(42+2)U2−U1=Kq02a(32−2)

Related Learning Resources & Exam Preparation

JEE Main PYQ Question Bank
Browse year-wise authentic previous years' questions with solutions
Authentic CBT Mock Tests
Simulate official exam environment with live timer and percentile scoring