QJEEM25Phbd63: JEE Main 2025 Physics - Class 11 JEEM25Phbd63 Solution: For an experimental expression , where all the digits are…

$$32.3(3\text{sig figs}),1125(4\text{sig figs}),27.4(3\text{sig figs})$$

In multiplication and division, the final answer must be reported with the same number of significant figures as the factor with the fewest significant figures, which here is 3.

First, calculate the unrounded result:

$$y=\frac{32.3\times 1125}{27.4}\approx \frac{36337.5}{27.4}\approx 1326.186$$

Expressing $1326.186$ in scientific notation:

$$1326.186\approx 1.326186\times {10}^3$$

Rounding to 3 significant figures:

The first three significant digits are 1, 3, and 2.

Considering the fourth digit (6) causes the last significant digit to round up.

Thus,

$$1.326186\times {10}^3\approx 1.33\times {10}^3$$

In standard decimal form, this is written as:

$$1330$$

Hence, the final reported value is:

$$y=1330$$