Verified Solution • 2025–26 Session moderate

QJEEM25Phb484: JEE Main 2025 Physics - Class 12 JEEM25Phb484 Solution: A uniform magnetic field of 0.4 T acts perpendicular to a…

A uniform magnetic field of 0.4 T acts perpendicular to a circular copper disc 20 cm in radius. The disc is having a uniform angular velocity of 10 π\pi rad s-1 about an axis through its centre and perpendicular to the disc. What is the potential difference developed between the axis of the disc and the rim? (π=3.14)(\pi=3.14)

Multiple Choice Options

  • A 0.5024 V
  • B 0.0628 V
  • C 0.2512 V
  • D 0.1256 V

Step-by-Step Verified Solution

amp;B=0.4 Tamp;r=20 cmamp;ω=10πrad/samp;E=12 BωR2amp;=0.2512 V\begin{aligned}& \mathrm{B}=0.4 \mathrm{~T} \\& \mathrm{r}=20 \mathrm{~cm} \\& \omega=10 \pi \mathrm{rad} / \mathrm{s} \\& \mathrm{E}=\frac{1}{2} \mathrm{~B} \omega \mathrm{R}^2 \\& =0.2512 \mathrm{~V}\end{aligned}

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