a m p ; 1 2 m × 100 + 0 = 1 2 m V B 2 + m g ( R − R 3 2 ) a m p ; 100 = V B 2 + 2 g R ( 1 − 3 2 ] a m p ; V B 2 = 100 − 20 ( 2 − 3 ) a m p ; V B 2 = 60 + 20 3 ) a m p ; K E E B = 1 2 m V B 2 = m 2 ( 60 + 20 3 ) a m p ; 1 2 m ( 100 ) = 1 2 m V C 2 + m g ( 3 R 2 ) \begin{aligned}& \frac{1}{2} \mathrm{~m} \times 100+0=\frac{1}{2} \mathrm{mV}_{\mathrm{B}}^2+\mathrm{mg}\left(\mathrm{R}-\frac{\mathrm{R} \sqrt{3}}{2}\right) \\& 100=\mathrm{V}_{\mathrm{B}}^2+2 \mathrm{gR}\left(1-\frac{\sqrt{3}}{2}\right] \\& \mathrm{V}_{\mathrm{B}}^2=100-20(2-\sqrt{3}) \\& \left.\mathrm{V}_{\mathrm{B}}^2=60+20 \sqrt{3}\right) \\& \mathrm{K}_{\mathrm{E}} \mathrm{E}_{\mathrm{B}}=\frac{1}{2} \mathrm{mV}_{\mathrm{B}}^2=\frac{\mathrm{m}}{2}(60+20 \sqrt{3}) \\& \frac{1}{2} \mathrm{~m}(100)=\frac{1}{2} \mathrm{mV}_{\mathrm{C}}^2+\mathrm{mg}\left(\frac{3 \mathrm{R}}{2}\right)\end{aligned} am p ; 2 1 m × 100 + 0 = 2 1 mV B 2 + mg ( R − 2 R 3 ) am p ; 100 = V B 2 + 2 gR ( 1 − 2 3 ] am p ; V B 2 = 100 − 20 ( 2 − 3 ) am p ; V B 2 = 60 + 20 3 ) am p ; K E E B = 2 1 mV B 2 = 2 m ( 60 + 20 3 ) am p ; 2 1 m ( 100 ) = 2 1 mV C 2 + mg ( 2 3 R )
a m p ; 100 = V C 2 = 60 a m p ; V C 2 = 40 a m p ; K ⋅ E C = 1 2 m V C 2 = 1 2 m ( 40 ) a m p ; K ⋅ E B = 60 + 20 3 40 = 3 2 + 3 2 = 3 + 3 2 \begin{aligned}& 100=V_{\mathrm{C}}^2=60 \\& \mathrm{~V}_{\mathrm{C}}^2=40 \\& \mathrm{~K} \cdot \mathrm{E}_{\mathrm{C}}=\frac{1}{2} m V_{\mathrm{C}}^2=\frac{1}{2} \mathrm{~m}(40) \\& \mathrm{K} \cdot \mathrm{E}_{\mathrm{B}}=\frac{60+20 \sqrt{3}}{40}=\frac{3}{2}+\frac{\sqrt{3}}{2}=\frac{3+\sqrt{3}}{2}\end{aligned} am p ; 100 = V C 2 = 60 am p ; V C 2 = 40 am p ; K ⋅ E C = 2 1 m V C 2 = 2 1 m ( 40 ) am p ; K ⋅ E B = 40 60 + 20 3 = 2 3 + 2 3 = 2 3 + 3
