Verified Solution • 2025–26 Session moderate

QJEEM25Ph9ebd: JEE Main 2025 Physics - Class 12 JEEM25Ph9ebd Solution: If and are de Broglie wavelength and kinetic energy,…

If λ\lambda and KK are de Broglie wavelength and kinetic energy, respectively, of a particle with constant mass. The correct graphical representation for the particle will be :

Multiple Choice Options

  • A https://ik.imagekit.io/novatra/photos/cba95acf2b10d90d8b277b6c6d0ffd1617974a98c04c235180951567073a2a3c.webp
  • B https://ik.imagekit.io/novatra/photos/e92c53184b009e6e2ef595c8ce05873ea9a62a657d010766dd07ebc1ec6d27e3.webp
  • C https://ik.imagekit.io/novatra/photos/1e878467df9fba2dd5276a7e4f032bab8a32458a29586eb9513fcdf2cde240ad.webp
  • D https://ik.imagekit.io/novatra/photos/78bab2ed61fb9874646cea7ad7582ea4a6d3195e7a89aa4bc8044d7b4183d1bd.webp

Step-by-Step Verified Solution

amp;amp;λ=hmv=h2mKamp;λ2=h22 m(1k)amp;Y=cx2amp; Upward facing parabola passing through origin. \begin{aligned}&\begin{aligned}& \lambda=\frac{\mathrm{h}}{\mathrm{mv}}=\frac{\mathrm{h}}{\sqrt{2 \mathrm{mK}}} \\& \lambda^2=\frac{\mathrm{h}^2}{2 \mathrm{~m}}\left(\frac{1}{\mathrm{k}}\right) \\& \mathrm{Y}=\mathrm{cx}^2\end{aligned}\\&\text { Upward facing parabola passing through origin. }\end{aligned}

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