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QJEEM25Ph8e76: JEE Main 2025 Physics - Class 12 JEEM25Ph8e76 Solution: A parallel plate capacitor of area and separation between the…

A parallel plate capacitor of area A=16 cm2A=16 \mathrm{~cm}^2 and separation between the plates 10 cm , is charged by a DC current. Consider a hypothetical plane surface of area A0=3.2 cm2\mathrm{A}_0=3.2 \mathrm{~cm}^2 inside the capacitor and parallel to the plates. At an instant, the current through the circuit is 6A. At the same instant the displacement current through A0\mathrm{A}_0 is __________ mA .

Step-by-Step Verified Solution

amp;Jd=I A=616amp;∴ I through small area =Jd×A′=616×3.2=amp;1.2 A=1200 mA\begin{aligned}& \mathrm{J}_{\mathrm{d}}=\frac{\mathrm{I}}{\mathrm{~A}}=\frac{6}{16} \\& \therefore \text { I through small area }=\mathrm{J}_{\mathrm{d}} \times A^{\prime}=\frac{6}{16} \times 3.2= \\& 1.2 \mathrm{~A}=1200 \mathrm{~mA}\end{aligned}

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