Verified Solution • 2025–26 Session moderate

QJEEM25Ph674e: JEE Main 2025 Physics - Class 12 JEEM25Ph674e Solution: An infinite wire has a circular bend of radius a , and carrying …

JEE Main 2025 (Online) 28th January Evening Shift Physics - Magnetic Effect of Current Question 10 English

An infinite wire has a circular bend of radius a, and carrying a current I as shown in the figure. The magnitude of magnetic field at the origin O of the arc is given by:

Multiple Choice Options

  • A μ02πIa[π2+2]\frac{\mu_0}{2 \pi} \frac{\mathrm{I}}{\mathrm{a}}\left[\frac{\pi}{2}+2\right]
  • B μ04πIa[3π2+1]\frac{\mu_0}{4 \pi} \frac{\mathrm{I}}{\mathrm{a}}\left[\frac{3 \pi}{2}+1\right]
  • C μ04πIa[π2+1]\frac{\mu_0}{4 \pi} \frac{\mathrm{I}}{\mathrm{a}}\left[\frac{\pi}{2}+1\right]
  • D μ04πIa[3π2+2]\frac{\mu_0}{4 \pi} \frac{\mathrm{I}}{\mathrm{a}}\left[\frac{3 \pi}{2}+2\right]

Step-by-Step Verified Solution

JEE Main 2025 (Online) 28th January Evening Shift Physics - Magnetic Effect of Current Question 10 English Explanation

amp;B1=μ0i4πa⊗amp; B2=μ04πia(3π2)⊗amp;B3=0amp; B=μ04πia(13π2)⊗\begin{aligned}& \mathrm{B}_1=\frac{\mu_0 \mathrm{i}}{4 \pi \mathrm{a}} \otimes \\& \mathrm{~B}_2=\frac{\mu_0}{4 \pi} \frac{\mathrm{i}}{\mathrm{a}}\left(\frac{3 \pi}{2}\right) \otimes \\& \mathrm{B}_3=0 \\& \mathrm{~B}=\frac{\mu_0}{4 \pi} \frac{\mathrm{i}}{\mathrm{a}}\left(1 \frac{3 \pi}{2}\right) \otimes\end{aligned}

Related Learning Resources & Exam Preparation

JEE Main PYQ Question Bank
Browse year-wise authentic previous years' questions with solutions
Authentic CBT Mock Tests
Simulate official exam environment with live timer and percentile scoring