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QJEEM25Ph62b2: JEE Main 2025 Physics - Class 11 JEEM25Ph62b2 Solution: A particle is projected at an angle of from horizontal at a…

A particle is projected at an angle of 30∘30^{\circ} from horizontal at a speed of 60 m/s60 \mathrm{~m} / \mathrm{s} . The height traversed by the particle in the first second is h0\mathrm{h}_0 and height traversed in the last second, before it reaches the maximum height, is h1h_1 . The ratio h0:h1h_0: h_1 is __________.

[Take, g=10 m/s2\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^2 ]

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JEE Main 2025 (Online) 22nd January Morning Shift Physics - Motion in a Plane Question 4 English Explanation

amp;S1=30×1−12×10×1=25amp; S3=30+(−102)×(2×3−1)=5amp; S1 S3=255=5\begin{aligned}& \mathrm{S}_1=30 \times 1-\frac{1}{2} \times 10 \times 1=25 \\& \mathrm{~S}_3=30+\left(\frac{-10}{2}\right) \times(2 \times 3-1)=5 \\& \frac{\mathrm{~S}_1}{\mathrm{~S}_3}=\frac{25}{5}=5\end{aligned}

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