Verified Solution • 2025–26 Session moderate

QJEEM25Ph5dad: JEE Main 2025 Physics - Class 12 JEEM25Ph5dad Solution: A thin prism with angle made of glass having refractive index…

A thin prism P1\mathrm{P}_1 with angle 4∘4^{\circ} made of glass having refractive index 1.54 , is combined with another thin prism P2\mathrm{P}_2 made of glass having refractive index 1.72 to get dispersion without deviation. The angle of the prism P2\mathrm{P}_2 in degrees is

Multiple Choice Options

  • A 1.5
  • B `16/3
  • C 3
  • D 4

Step-by-Step Verified Solution

We know, for thin prism,

μ=A+δA

where, μ\mu = refractive index

A = Angle of prism

δ\delta = Angle of deviation

We can write, μA=A+δ

⇒δ=(μ−1)A

given, δnet=0

⇒(μ1−1)A1−(μ2−1)A2=0

⇒(1.54−1)4−(1.72−1)A2=0

⇒A2=54×472⇒A2=3∘

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