QJEEM25Ph55d0: JEE Main 2025 Physics - Class 12 JEEM25Ph55d0 Solution: The number of spectral lines emitted by atomic hydrogen that is …

When an e transition from n $^{th}$ to ground state then $\sum {(n - 1)}$ spectral lines are produced.

Given, $n=4$

So, $\sum {(4 - 1) = \sum {3 = 3 + 2 + 1 = 6} }$

Hence, 6 spectral lines are emitted by atomic Hydrogen that is in the $4^{th}$ energy level