Verified Solution • 2025–26 Session moderate

QJEEM25Ph40e7: JEE Main 2025 Physics - Class 11 JEEM25Ph40e7 Solution: Two spherical bodies of same materials having radii 0.2 m and…

Two spherical bodies of same materials having radii 0.2 m and 0.8 m are placed in same atmosphere. The temperature of the smaller body is 800 K and temperature of the bigger body is 400 K . If the energy radiated from the smaller body is E, the energy radiated from the bigger body is (assume, effect of the surrounding temperature to be negligible),

Multiple Choice Options

  • A 64 E
  • B 16 E
  • C E
  • D 256 E

Step-by-Step Verified Solution

amp;dθdt=σeATamp;Psmaller Plarger =(0.2)2×8004(0.8)2×4004amp;116×16=1amp;∴Plarger =Psmaller \begin{aligned}& \frac{\mathrm{d} \theta}{\mathrm{dt}}=\sigma \mathrm{eAT} \\& \frac{\mathrm{P}_{\text {smaller }}}{\mathrm{P}_{\text {larger }}}=\frac{(0.2)^2 \times 800^4}{(0.8)^2 \times 400^4} \\& \frac{1}{16} \times 16=1 \\& \therefore \mathrm{P}_{\text {larger }}=\mathrm{P}_{\text {smaller }}\end{aligned}

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